Q1	50 oC	300 oD
Q2	20 oC	180 oD
Q3	-100 oC	-300 oD
Q4	37 oC	248oD
Q5	1000 oC	4100 oD

Here is how it is done...

Let's draw a little diagram to compare the temperature scales...

We can put in the boiling and melting points and the midway temperatures of 50 ^oC and 300 ^oD

So the first question can be answered by inspection...

 

We can calculate that each change in temperature of 1 ^oC is equivalent to a change in temperature on the Dalek scale of 4 ^oD

 

20 ^oC is therefore

20 x 4 = 80 degrees D higher than the temperature of melting ice in degrees D ( = 100^oD)

so it is 100 + 80 = 180^oD

 

-100 ^oC is therefore

400 degrees D lower than the temperature of melting icein degrees D ( = 100^oD)

so it is 100 - 400 = -300^oD

 

37^oC is therefore 37 x 4 = 148 degrees D higher than the temperature of melting ice in degrees D ( = 100^oD)

so it is 100 + 148= 148^oD

 

and

1000^oC is therefore 1000 x 4 = 4000 degrees D higher than the temperature of melting ice in degrees D ( = 100^oD)

so it is 100 + 4000 = 4100^oD

LOJ January 2003